例子

如果获取到的数据格式是如下的

var arr = [
		    {"id":"1001","name":"值1","value":"111"},
		    {"id":"1002","name":"值2","value":"222"},
		    {"id":"1002","name":"值2","value":"333"},
		    {"id":"1003","name":"值3","value":"444"},
		    {"id":"1003","name":"值3","value":"555"},
		    {"id":"1003","name":"值3","value":"666"}
		];

需要进行如下处理

		var map = {},
		    dest = [];
		for(var i = 0; i < arr.length; i++){
		    var ai = arr[i];
            //根据id属性来分组
            //如果id属性的值不存在则在对象中创建id属性
		    if(!map[ai.id]){
		        dest.push({
		            id: ai.id,
		            name: ai.name,
		            data: [ai]
		        });
		        map[ai.id] = ai;
		    }else{
		        for(var j = 0; j < dest.length; j++){
		            var dj = dest[j];
                	//否则遍历出相同的id并且把值push进去
		            if(dj.id == ai.id){
		                dj.data.push(ai);
		                break;
		            }
		        }
		    }
		}
		
		console.log(dest);

打印的结果为

根据id来分组，将id值相同的分到同一个组里

亲测有效，奔走相告。